?!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> Java中的递归原理分析-南软g开发|׃软g开?南赢dU技软g开发公?/title> <meta name="keywords" content="Java中的递归原理分析"/> <meta name="description" content="解释Q程序调用自w的~程技巧叫做递归。程序调用自w的~程技巧称为递归QrecursionQ。递归做ؓ一U算法在E序设计语言中广泛应用。一个过E或函数在其定义或说明中有直接或间接调用自n的一U方法,它通常把一个大型复"/> <link href="/css/style.css" rel="stylesheet" type="text/css" /> <meta http-equiv="Cache-Control" content="no-transform" /> <meta http-equiv="Cache-Control" content="no-siteapp" /> </head> <body> <div style="position:fixed;left:-9000px;top:-9000px;"><dfn id="orz4q"><noscript id="orz4q"><xmp id="orz4q"><output id="orz4q"></output></xmp></noscript></dfn><strong id="orz4q"><dl id="orz4q"></dl></strong><ol id="orz4q"><p id="orz4q"><nav id="orz4q"><pre id="orz4q"></pre></nav></p></ol><dfn id="orz4q"></dfn><small id="orz4q"><optgroup id="orz4q"></optgroup></small><center id="orz4q"><small id="orz4q"><track id="orz4q"><rp 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href="/">南软g开?/a> 览ơ数Q?Script Language="Javascript" Src="/item/GetHits.asp?Action=Count&GetFlag=0&m=1&ID=2889"></Script></div> <div class="article_main"><div id="MyContent"><p><strong><span style="font-size: 14px;">解释Q程序调用自w的~程技巧叫做递归?/span></strong></p><p><span style="font-size: 14px;">E序调用自n的编E技巧称为递归Q?recursionQ。递归做ؓ一U算法在E序设计语言中广泛应用?一个过E或函数在其定义或说明中有直接或间接调用自n的一U方法,它通常把一个大型复杂的问题层层转化Z个与原问题相似的规模较小的问题来求解Q递归{略只需量的程序就可描q出解题q程所需要的多次重复计算Q大大地减少了程序的代码量。递归的能力在于用有限的语句来定义对象的无限集合?/span></p><p><span style="font-size: 14px;"> </span></p><p><span style="font-size: 14px;">递归的三个条Ӟ<br style="margin: 0px; padding: 0px;"/> </span></p><p><span style="font-size: 14px;"><strong style="margin: 0px; padding: 0px;">边界条g</strong></span></p><p><span style="font-size: 14px;"><strong style="margin: 0px; padding: 0px;">递归前进D?/strong></span></p><p><span style="font-size: 14px;"><strong style="margin: 0px; padding: 0px;">递归q回D?/strong></span></p><p><span style="font-size: 14px;"><strong style="margin: 0px; padding: 0px;">当边界条件不满Ӟ递归前进Q当边界条g满Ӟ递归q回?/strong></span></p><p><span style="font-size: 14px;"> </span></p><p><span style="font-size: 14px;">下面通过两个CZE序来说明:</span></p><p><span style="font-size: 14px;">使用Java代码?的阶乘。(5的阶?5*4*3*2*1Q?/span></p><p><span style="font-size: 14px;"> </span></p><p><span style="font-size: 14px;">[java]  </span></p><p><span style="font-size: 14px;">package org.wxp.recursion;  </span></p><p><span style="font-size: 14px;">  </span></p><p><span style="font-size: 14px;">/** </span></p><p><span style="font-size: 14px;"> * 计算5的阶?result = 5*4*3*2*1) </span></p><p><span style="font-size: 14px;"> * @author Champion.Wong </span></p><p><span style="font-size: 14px;"> *  </span></p><p><span style="font-size: 14px;"> * </span></p><p><span style="font-size: 14px;"> */  </span></p><p><span style="font-size: 14px;">public class Test01 {  </span></p><p><span style="font-size: 14px;">    public static void main(String[] args) {  </span></p><p><span style="font-size: 14px;">        System.out.println(f(5));  </span></p><p><span style="font-size: 14px;">    }  </span></p><p><span style="font-size: 14px;">      </span></p><p><span style="font-size: 14px;">    public static int f(int n) {  </span></p><p><span style="font-size: 14px;">        if (1 == n)   </span></p><p><span style="font-size: 14px;">            return 1;  </span></p><p><span style="font-size: 14px;">        else   </span></p><p><span style="font-size: 14px;">            return n*(n-1);  </span></p><p><span style="font-size: 14px;">    }  </span></p><p><span style="font-size: 14px;">}  </span></p><p><a href="javascript:;" onclick="showimg('http://982867735.p128878.sqnet.cn/UploadFiles/2016-11-07/20161172512549366.png');"><img src="http://982867735.p128878.sqnet.cn/UploadFiles/2016-11-07/20161172512549366.png" alt="Java中的递归原理分析" onmousewheel="return bbimg(this)" onload="javascript:resizepic(this)" border="0"/></a></p><p><span style="font-size: 14px;"> </span></p><p><span style="font-size: 14px;"> </span></p><p><span style="font-size: 14px;">此题中,按照递归的三个条件来分析Q?/span></p><p><span style="font-size: 14px;">(1)边界条gQ阶乘,乘到最后一个数Q即1的时候,q回1Q程序执行到底;</span></p><p><span style="font-size: 14px;">(2)递归前进D:当前的参C{于1的时候,l箋调用自nQ?/span></p><p><span style="font-size: 14px;">(3)递归q回D:从最大的数开始乘Q如果当前参数是5Q那么就?*4Q即5*(5-1)Q即n*(n-1)</span></p><p><span style="font-size: 14px;"> </span></p><p><span style="font-size: 14px;">使用Java代码求数列:1Q?Q?Q?Q?Q?......W?0位的?/span></p><p><span style="font-size: 14px;">[java]  </span></p><p><span style="font-size: 14px;">package org.wxp.recursion;  </span></p><p><span style="font-size: 14px;">  </span></p><p><span style="font-size: 14px;">/** </span></p><p><span style="font-size: 14px;"> * 求数列:1Q?Q?Q?Q?Q?......W?0位的?nbsp;</span></p><p><span style="font-size: 14px;"> * @author Champion.Wong </span></p><p><span style="font-size: 14px;"> *  </span></p><p><span style="font-size: 14px;"> */  </span></p><p><span style="font-size: 14px;">public class Test_02_Fibonacci {  </span></p><p><span style="font-size: 14px;">    public static void main(String[] args) {  </span></p><p><span style="font-size: 14px;">        System.out.println(f(6));  </span></p><p><span style="font-size: 14px;">    }  </span></p><p><span style="font-size: 14px;">      </span></p><p><span style="font-size: 14px;">    public static int f(int n ) {  </span></p><p><span style="font-size: 14px;">        if (1== n || 2 == n)   </span></p><p><span style="font-size: 14px;">            return 1;  </span></p><p><span style="font-size: 14px;">        else  </span></p><p><span style="font-size: 14px;">            return f(n-1) + f(n-2);  </span></p><p><span style="font-size: 14px;">    }  </span></p><p><span style="font-size: 14px;">}  </span></p><p><span style="font-size: 14px;"> </span></p><p><span style="font-size: 14px;"><strong style="margin: 0px; padding: 0px;">心得Q有些初学者可能认为递归x自己调用自己Q那岂不是死循环了。对Q如果递归写的不合理,那就是死循环了。但是如果写的合理,加上“边界条件”,E序执行到底的时候,会逐层q回。就像我们爬׃P我们l着p\爬上一层又一层,如果没有山顶Q我们会一直往上爬。但如果C山顶Q就按照上山时候的步骤一层一层的往下爬?/strong></span></p><p><span style="font-size: 14px;"><strong style="margin: 0px; padding: 0px;"><br/></strong></span></p><p><br/></p></div> </div> </div> </div> <div class="clear"></div> <div class="foot"> <div class="foot_menu"> <ul> <li><a href="/About/">关于我们</a></li> <li><a href="/Advantage/">开发优?/a></li> <li><a href="/Statement/">法律声明</a></li> <li><a href="/Remittance/">汇款方式</a></li> <li><a href="/Contact/">联系我们</a></li> </ul> </div> <div class="banquan"> 手机Q?8678812288 EQMail:1069706080@qq.com<br /> 地址Q山东省南市舜耕\泉城公园东门园内向北50c? 鲁ICP?7011972? 版权所?008Q?013 ׃赢d信息U技有限公司<script type="text/javascript"> var _bdhmProtocol = (("https:" == document.location.protocol) ? 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